Well need to change the circuit first to this you could also just remove the 10k resistor to gnd from the previous circuit. You can think of an open drain gpio as behaving like a switch which is either connected to ground or disconnected.
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A push button is connected to gnd.
Pull up resistor gpio. Its the same thing but in reverse. But while configuring a gpio pin which will be connected to an led what is the use of these settings. Now connect the other contact of the button to ground.
I tried no pull up and pull down and pull up for example but i could not see a difference in the implementation. Now lets look at the opposite. When the push button is not pressed the nand gate input is high.
I understand why and how to use a pull updown resistor when using a button gpio input. If you call the gpiopinwrite method for this pin with a value of gpiopinvaluelow the method produces a low impedance low state. Configures the gpio pin in open drain mode with resistive pull up mode.
Ill show this in effect later pull up. You need a pull down resistor connecting your circuit to ground so that it reads low when the circuit is open. When you pressed the button the gpio will be 0.
Connect a resistor of suitable value between 33 volts and the gpio pin and one of the push buttons contacts to the gpio pin also. Similarly if you have a circuit connecting your gpio pin to ground when its closed itll read low. You need a pull up resistor so that when its open it defaults to the high state.
The resistor and the button now form a potential divider. While the button is not pressed the gpio will register a 1. In order to achieve a logical high output on the line a pull up resistor is used to connect the open drain output to the desired output voltage level.
When a push button is pressed the nand gate input is low. I am using stm32f407 disc. Gpiosetupportorpin gpioin pullupdowngpiopuddown how does that apply to our program.
A pull up resistor is connected to the first input of the nand gate and positive voltage.
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