That is the faster you try to make it change the more it resists. We replace the voltage source with a short circuit at t 0.

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If i used this circuit to charge and discharge the inductor will there be any voltage spikes.

Inductor discharge voltage. Inductors have the exact opposite characteristics of capacitors. Now connected to the resistive load ie. Explains the charging and discharging of an inductor in an rl circuit with a dc source.
This inductor voltage calculator calculates the voltage across an inductor based on the inductance l of the inductor and the current that flows across the inductor. A lr series circuit consists basically of an inductor of inductance l connected in series with a resistor of resistance r. Whereas capacitors store energy in an electric field produced by the voltage between two plates inductors store energy in a magnetic field produced by the current through wire.
An inductor resists changes to the flow of current. In the following circuit the inductor initially has current i0 vs r flowing through it. When a battery is connected to a series resistor and inductor the inductor resists the change in current and the current therefore builds up slowlyacting in accordance with faradays law and lenzs law the amount of impedance to the buildup of current is proportional to the rate of change of the current.
If i understand this correctly this only happens when there is no way for the current to go so voltage builds up but then again there is a small split of second between the switching between the 2 circuits will that cause such a problem. After we cut out the voltage source the voltage across the inductor is i0 r but the higher voltage is now at the negative terminal of the inductor. The resistance r is the dc resistive value of the wire turns or loops that goes into making up the inductors coil.
Reviews how the current and voltage change over time during the charging and discharging phases. Actually the current does not change direction. The energy stored will be discharged to a resistive load and will be dissipated in the resistor.
Drive a current into an inductor with say positive at end a and negative at. Thus while the stored energy in a capacitor tries to maintain a constant voltage across its terminals the stored energy in an inductor tries to. Suppose the above inductor is charged has stored energy in the magnetic field around it and has been disconnected from the voltage source.
The formula which calculates the inductor voltage is v ldidt where v is the voltage across the inductor l is the inductance of the inductor and didt is the derivative of. What happens is the polarity across the inductor changes direction. The switch is moved to position 2 at the time t0.

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